Optimal. Leaf size=160 \[ -\frac{a^2 (10 A+9 B) \sin ^3(c+d x)}{15 d}+\frac{a^2 (10 A+9 B) \sin (c+d x)}{5 d}+\frac{a^2 (5 A+6 B) \sin (c+d x) \cos ^3(c+d x)}{20 d}+\frac{a^2 (7 A+6 B) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{1}{8} a^2 x (7 A+6 B)+\frac{B \sin (c+d x) \cos ^3(c+d x) \left (a^2 \cos (c+d x)+a^2\right )}{5 d} \]
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Rubi [A] time = 0.277828, antiderivative size = 160, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.226, Rules used = {2976, 2968, 3023, 2748, 2635, 8, 2633} \[ -\frac{a^2 (10 A+9 B) \sin ^3(c+d x)}{15 d}+\frac{a^2 (10 A+9 B) \sin (c+d x)}{5 d}+\frac{a^2 (5 A+6 B) \sin (c+d x) \cos ^3(c+d x)}{20 d}+\frac{a^2 (7 A+6 B) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{1}{8} a^2 x (7 A+6 B)+\frac{B \sin (c+d x) \cos ^3(c+d x) \left (a^2 \cos (c+d x)+a^2\right )}{5 d} \]
Antiderivative was successfully verified.
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Rule 2976
Rule 2968
Rule 3023
Rule 2748
Rule 2635
Rule 8
Rule 2633
Rubi steps
\begin{align*} \int \cos ^2(c+d x) (a+a \cos (c+d x))^2 (A+B \cos (c+d x)) \, dx &=\frac{B \cos ^3(c+d x) \left (a^2+a^2 \cos (c+d x)\right ) \sin (c+d x)}{5 d}+\frac{1}{5} \int \cos ^2(c+d x) (a+a \cos (c+d x)) (a (5 A+3 B)+a (5 A+6 B) \cos (c+d x)) \, dx\\ &=\frac{B \cos ^3(c+d x) \left (a^2+a^2 \cos (c+d x)\right ) \sin (c+d x)}{5 d}+\frac{1}{5} \int \cos ^2(c+d x) \left (a^2 (5 A+3 B)+\left (a^2 (5 A+3 B)+a^2 (5 A+6 B)\right ) \cos (c+d x)+a^2 (5 A+6 B) \cos ^2(c+d x)\right ) \, dx\\ &=\frac{a^2 (5 A+6 B) \cos ^3(c+d x) \sin (c+d x)}{20 d}+\frac{B \cos ^3(c+d x) \left (a^2+a^2 \cos (c+d x)\right ) \sin (c+d x)}{5 d}+\frac{1}{20} \int \cos ^2(c+d x) \left (5 a^2 (7 A+6 B)+4 a^2 (10 A+9 B) \cos (c+d x)\right ) \, dx\\ &=\frac{a^2 (5 A+6 B) \cos ^3(c+d x) \sin (c+d x)}{20 d}+\frac{B \cos ^3(c+d x) \left (a^2+a^2 \cos (c+d x)\right ) \sin (c+d x)}{5 d}+\frac{1}{4} \left (a^2 (7 A+6 B)\right ) \int \cos ^2(c+d x) \, dx+\frac{1}{5} \left (a^2 (10 A+9 B)\right ) \int \cos ^3(c+d x) \, dx\\ &=\frac{a^2 (7 A+6 B) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a^2 (5 A+6 B) \cos ^3(c+d x) \sin (c+d x)}{20 d}+\frac{B \cos ^3(c+d x) \left (a^2+a^2 \cos (c+d x)\right ) \sin (c+d x)}{5 d}+\frac{1}{8} \left (a^2 (7 A+6 B)\right ) \int 1 \, dx-\frac{\left (a^2 (10 A+9 B)\right ) \operatorname{Subst}\left (\int \left (1-x^2\right ) \, dx,x,-\sin (c+d x)\right )}{5 d}\\ &=\frac{1}{8} a^2 (7 A+6 B) x+\frac{a^2 (10 A+9 B) \sin (c+d x)}{5 d}+\frac{a^2 (7 A+6 B) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a^2 (5 A+6 B) \cos ^3(c+d x) \sin (c+d x)}{20 d}+\frac{B \cos ^3(c+d x) \left (a^2+a^2 \cos (c+d x)\right ) \sin (c+d x)}{5 d}-\frac{a^2 (10 A+9 B) \sin ^3(c+d x)}{15 d}\\ \end{align*}
Mathematica [A] time = 0.39821, size = 108, normalized size = 0.68 \[ \frac{a^2 (60 (12 A+11 B) \sin (c+d x)+240 (A+B) \sin (2 (c+d x))+80 A \sin (3 (c+d x))+15 A \sin (4 (c+d x))+420 A d x+90 B \sin (3 (c+d x))+30 B \sin (4 (c+d x))+6 B \sin (5 (c+d x))+360 B c+360 B d x)}{480 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.076, size = 186, normalized size = 1.2 \begin{align*}{\frac{1}{d} \left ({a}^{2}A \left ({\frac{\sin \left ( dx+c \right ) }{4} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+{\frac{3\,\cos \left ( dx+c \right ) }{2}} \right ) }+{\frac{3\,dx}{8}}+{\frac{3\,c}{8}} \right ) +{\frac{B{a}^{2}\sin \left ( dx+c \right ) }{5} \left ({\frac{8}{3}}+ \left ( \cos \left ( dx+c \right ) \right ) ^{4}+{\frac{4\, \left ( \cos \left ( dx+c \right ) \right ) ^{2}}{3}} \right ) }+{\frac{2\,{a}^{2}A \left ( 2+ \left ( \cos \left ( dx+c \right ) \right ) ^{2} \right ) \sin \left ( dx+c \right ) }{3}}+2\,B{a}^{2} \left ( 1/4\, \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+3/2\,\cos \left ( dx+c \right ) \right ) \sin \left ( dx+c \right ) +3/8\,dx+3/8\,c \right ) +{a}^{2}A \left ({\frac{\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{2}}+{\frac{dx}{2}}+{\frac{c}{2}} \right ) +{\frac{B{a}^{2} \left ( 2+ \left ( \cos \left ( dx+c \right ) \right ) ^{2} \right ) \sin \left ( dx+c \right ) }{3}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.975302, size = 240, normalized size = 1.5 \begin{align*} -\frac{320 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} A a^{2} - 15 \,{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} A a^{2} - 120 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} A a^{2} - 32 \,{\left (3 \, \sin \left (d x + c\right )^{5} - 10 \, \sin \left (d x + c\right )^{3} + 15 \, \sin \left (d x + c\right )\right )} B a^{2} + 160 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} B a^{2} - 30 \,{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} B a^{2}}{480 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.39993, size = 271, normalized size = 1.69 \begin{align*} \frac{15 \,{\left (7 \, A + 6 \, B\right )} a^{2} d x +{\left (24 \, B a^{2} \cos \left (d x + c\right )^{4} + 30 \,{\left (A + 2 \, B\right )} a^{2} \cos \left (d x + c\right )^{3} + 8 \,{\left (10 \, A + 9 \, B\right )} a^{2} \cos \left (d x + c\right )^{2} + 15 \,{\left (7 \, A + 6 \, B\right )} a^{2} \cos \left (d x + c\right ) + 16 \,{\left (10 \, A + 9 \, B\right )} a^{2}\right )} \sin \left (d x + c\right )}{120 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 3.41671, size = 459, normalized size = 2.87 \begin{align*} \begin{cases} \frac{3 A a^{2} x \sin ^{4}{\left (c + d x \right )}}{8} + \frac{3 A a^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{4} + \frac{A a^{2} x \sin ^{2}{\left (c + d x \right )}}{2} + \frac{3 A a^{2} x \cos ^{4}{\left (c + d x \right )}}{8} + \frac{A a^{2} x \cos ^{2}{\left (c + d x \right )}}{2} + \frac{3 A a^{2} \sin ^{3}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{8 d} + \frac{4 A a^{2} \sin ^{3}{\left (c + d x \right )}}{3 d} + \frac{5 A a^{2} \sin{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{8 d} + \frac{2 A a^{2} \sin{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{d} + \frac{A a^{2} \sin{\left (c + d x \right )} \cos{\left (c + d x \right )}}{2 d} + \frac{3 B a^{2} x \sin ^{4}{\left (c + d x \right )}}{4} + \frac{3 B a^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{2} + \frac{3 B a^{2} x \cos ^{4}{\left (c + d x \right )}}{4} + \frac{8 B a^{2} \sin ^{5}{\left (c + d x \right )}}{15 d} + \frac{4 B a^{2} \sin ^{3}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{3 d} + \frac{3 B a^{2} \sin ^{3}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{4 d} + \frac{2 B a^{2} \sin ^{3}{\left (c + d x \right )}}{3 d} + \frac{B a^{2} \sin{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{d} + \frac{5 B a^{2} \sin{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{4 d} + \frac{B a^{2} \sin{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{d} & \text{for}\: d \neq 0 \\x \left (A + B \cos{\left (c \right )}\right ) \left (a \cos{\left (c \right )} + a\right )^{2} \cos ^{2}{\left (c \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.22221, size = 185, normalized size = 1.16 \begin{align*} \frac{B a^{2} \sin \left (5 \, d x + 5 \, c\right )}{80 \, d} + \frac{1}{8} \,{\left (7 \, A a^{2} + 6 \, B a^{2}\right )} x + \frac{{\left (A a^{2} + 2 \, B a^{2}\right )} \sin \left (4 \, d x + 4 \, c\right )}{32 \, d} + \frac{{\left (8 \, A a^{2} + 9 \, B a^{2}\right )} \sin \left (3 \, d x + 3 \, c\right )}{48 \, d} + \frac{{\left (A a^{2} + B a^{2}\right )} \sin \left (2 \, d x + 2 \, c\right )}{2 \, d} + \frac{{\left (12 \, A a^{2} + 11 \, B a^{2}\right )} \sin \left (d x + c\right )}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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